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4.9x^2-3.75x+0.2=0
a = 4.9; b = -3.75; c = +0.2;
Δ = b2-4ac
Δ = -3.752-4·4.9·0.2
Δ = 10.1425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.75)-\sqrt{10.1425}}{2*4.9}=\frac{3.75-\sqrt{10.1425}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.75)+\sqrt{10.1425}}{2*4.9}=\frac{3.75+\sqrt{10.1425}}{9.8} $
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